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Y+2=-3(x-4)?

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  • Y+2=-3(x-4)?


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Answer #3 | 10/10 2016 15:33
From your question Y + 2 = -3(x - 4) = -3(x - 4) = -3x + 12 = -3x + 10 + 2 Let Y = -3x + 10 = Y + 2 = (-3x + 10) + 2 Hence = Y + 2 = ( -3x + 10) + 2
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Answer #11 | 10/10 2016 13:11
y = - 3x + 10
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Answer #12 | 10/10 2016 20:11
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Answer #27 | 10/10 2016 15:23
y = -3x + 10 <<< slope intercept form
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Answer #28 | 10/10 2016 08:33
From your question Y + 2 = -3(x - 4) = -3(x - 4) = -3x + 12 = -3x + 10 + 2 Let Y = -3x + 10 = Y + 2 = (-3x + 10) + 2 Hence = Y + 2 = ( -3x + 10) + 2
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Answer #29 | 10/10 2016 15:28
y + 2 = -3(x − 4) <== This is a line in point-slope form. with a slope of m = -3 and passes though the point (4,-2) [ y − y₁ = m(x − x₁) ] ∴ y + 2 = -3x + 12 ∴ y = -3x + 10 <== the same line in slope-intercept form [ y = mx + b ] ∴ 3x + y = 10 <== the same line in standard form [ Ax + By = C ] ∴ 3x + y − 10 = 0 <== the same line in general form [ Ax + By + C = 0 ] the real question is what do want us to to do with the line. we can tell you the line crosses the y-axis at (0,10) and the x-axis at (10/3,0) and has a slope (aka gradient) of -3
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Answer #31 | 10/10 2016 08:28
y + 2 = -3(x − 4) <== This is a line in point-slope form. with a slope of m = -3 and passes though the point (4,-2) [ y − y₁ = m(x − x₁) ] ∴ y + 2 = -3x + 12 ∴ y = -3x + 10 <== the same line in slope-intercept form [ y = mx + b ] ∴ 3x + y = 10 <== the same line in standard form [ Ax + By = C ] ∴ 3x + y − 10 = 0 <== the same line in general form [ Ax + By + C = 0 ] the real question is what do want us to to do with the line. we can tell you the line crosses the y-axis at (0,10) and the x-axis at (10/3,0) and has a slope (aka gradient) of -3
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