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Which equation gives the directrix of y - 1/12x^2 - 5?

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  • Which equation gives the directrix of y - 1/12x^2 - 5?


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Answer #1 | 05/01 2014 11:45
I think you mean't to write the equation as: y = (1/12)x^2 - 5 Which can be rewritten as: (1/12)x^2 = y + 5 or x^2 = 12(y + 5) This equation is of the standard form: (x-h)^2 = 4py, with (h,k) being the (x,y) coordinates of the vertex. For given equation: Vertex: (0,-5) Axis of symmetry: x=0 or y-axis (parabola opens upwards). 4p = 12 p = 3 The directrix is p units below the vertex on the axis of symmetry. Equation of Directrix: y = -8 Hope this helps! (:

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