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What is the mole ratio of a compound containing 78g Potassium, 12g Carbon, and 48g Oxygen?

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  • What is the mole ratio of a compound containing 78g Potassium, 12g Carbon, and 48g Oxygen?


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Answer #1 | 06/06 2017 05:55
Start buy calculating how many moles of each element you have. https://www.youtube.com/watch?v=wnRaBWvhYKY
Positive: 50 %
Answer #2 | 06/06 2017 05:56
(78 g K) / (39.0983 g K/mol) = 1.9950 mol K (12 g C) / (12.01078 g C/mol) = 0.99910 mol C (48 g O) / (15.99943 g O/mol) = 3.0001 mol O Round to the nearest whole numbers to find the empirical formula (the coefficients of which are the mole ratios): K2CO3
Positive: 46.153846153846 %

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