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What is the mass of a cylinder of lead that is 1.80 in in diameter, and 4.12 in long. The density of lead is 11.4 g/mL.?

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  • What is the mass of a cylinder of lead that is 1.80 in in diameter, and 4.12 in long. The density of lead is 11.4 g/mL.?


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Answer #1 | 09/09 2014 05:48
Volume of lead = pi*(1.80 in/2)^2 * (4.12 in) * 16.3871 mL/in^3 = 171.80 mL So mass = (11.4 g/mL)(171.8 mL) = 1958.57 grams or 1.95857 kg
Positive: 66.666666666667 %
Answer #2 | 09/09 2014 05:47
Look up the volume for a cylinder. Convert your dimensions to cm. Calculate the volume in cm^3 Multiply the volume by the density (11.4 g/mL = 11.4 g/cm^3) Hint: it's not 316 kg
Positive: 60 %
Answer #3 | 09/09 2014 05:38
316 kg
Positive: 33.333333333333 %
Answer #4 | 09/09 2014 14:02
Volume of the cylinder: V = base_area * high → where high = 4.12 in V = base_area * 4.12 → where base_area = π.d²/4 V = (π.d²/4) * 4.12 → where d = 1.80 in V = (π * 1.80²/4) * 4.12 V = 4.12 * π * 1.80²/4 V = 1.03 * π * 1.80² V = 3.3372π ← this is cubic inches ← memorize this result as (1) You know that: 1 in = 2.54 cm → then you cube (1 in)³ = (2.54 cm)³ 1 * 1 * 1 * in * in * in = 2.54 * 2.54 * 2.54 * cm * cm * cm (1 * 1 * 1) * (in * in * in) = (2.54 * 2.54 * 2.54) * (cm * cm * cm) 1 in³ = 16.387064 cm³ ← memorize this result as (2) You know that: 1 ℓ = 1000 cm³ → then you divide by 1000 (1/1000) ℓ = (1000/1000) cm³ → you simplify 0.001 ℓ = 1 cm³ 1 mℓ = 1 cm³ ← memorize this result as (3) Recall (1): V = 3.3372π in³ V = 3.3372π * (1 in³) → recall (2) V = 3.3372π * 16.387064 cm³ → recall (3) V = 3.3372π * 16.387064 mℓ → you know that: 1 mℓ gives you 11.4 g V = 3.3372π * 16.387064 * 11.4 g V ≈ 1958.5655 g V ≈ 1.958 kg
Positive: 33.333333333333 %
Anonymous801036 | 19/06 2021 09:42
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