What is the length (in cm) of an edge of a cube of lead (density = 11.3 g/mL) which has a mass of 19.87 lb?

Answers

Answer #1 | 21/05 2017 09:58

One pound is equal to 453.6 g.
19.87 lb * (453.6 g)/(1 lb) = 9012.9 g
Volume = mass / density = 9012.9 g / (11.3 g/mL) = 797.6 mL
Since mL is just like a cm that got cubified, V = 797.6 cm^3
V = a^3
a = V^(1/3) = 9.27 cm

Answer #1| 21/05 2017 09:5854.838709677419 %