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What is the length (in cm) of an edge of a cube of lead (density = 11.3 g/mL) which has a mass of 19.87 lb?

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  • What is the length (in cm) of an edge of a cube of lead (density = 11.3 g/mL) which has a mass of 19.87 lb?


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Answer #1 | 21/05 2017 09:58
One pound is equal to 453.6 g. 19.87 lb * (453.6 g)/(1 lb) = 9012.9 g Volume = mass / density = 9012.9 g / (11.3 g/mL) = 797.6 mL Since mL is just like a cm that got cubified, V = 797.6 cm^3 V = a^3 a = V^(1/3) = 9.27 cm
Positive: 54.838709677419 %

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