What is the focus of the parabola given by the equation x = 1/44 y^2?

Answers

Answer #1 | 20/12 2013 00:09

this parabola has the x-axis as its axis of symmetry
___ the origin is its vertex
___ opening in the plus x direction
the vertex is midway between the focus and the directrix
___ the distance from the vertex to the focus (or the directrix) is labeled p
the coefficient "a" of the 2nd order (squared) term is equal to ___ 1 / 4p
in this case ___ 1 / 4p = 1 / 44 ___ p = 11
so the focus is ___ (11,0)

Answer #1| 20/12 2013 00:09