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The nth term of a geometrical progression is [ 2^(2n-1)]/3 for all values of n. Find first 3 terms of the series?

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  • The nth term of a geometrical progression is [ 2^(2n-1)]/3 for all values of n. Find first 3 terms of the series?


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Answer #1 | 23/07 2014 14:24
T1 = 2/3 T2 = 8/3 T3 = 32/3....... Common ratio is 4
Answer #2 | 23/07 2014 14:17
Tn = 2^(2n-1)]/3 T1 = 2^(2 - 1)/3 = 2/3 T2 = 2^(3)/3 = 8/3 T3 = 2^5/3 = 32/3 2/3, 8/3, 32/3

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