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the length of a rectangle is twice its width. if the perimeter of the rectangle is 42 yd find its area?

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  • the length of a rectangle is twice its width. if the perimeter of the rectangle is 42 yd find its area?


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Answer #1 | 19/12 2013 23:09
7 x 14 = 98yd
Answer #2 | 19/12 2013 23:11
L = 2*w 2(L + w) = 42 L + w = 21 2w + w = 21 3w = 21 w = 21/3 w = 7 L + w = 21 L + 7 = 21 L = 14
Answer #3 | 19/12 2013 23:11
Width ....... x Length ....2x P = 2(length) + 2(width) 42 = 2(2x) + 2(x) 42 = 4x + 2x 42 = 6x 7 = x <-- width If width = 7, then length = 14 So the dimensions of the rectangle are 7 yards by 14 yards Area = (length)(width) A = (7)(14) A = 98 square yards <-- answer Answer: The area of the rectangle is 98 square yards

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