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surface integral of v(r)?

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  • surface integral of v(r)?


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Answer #1 | 14/01 2014 14:25
you can use x and y for v and u. r = (x, y, z) z = sqrt(4 - x^2 - y^2)^1/2 dr/dx = (1, 0, dz/dx) dr/dy = (0, 1, dz/dy) dr/dx X dr/dy = (-dz/dx, -dz/dy, 1) = (x/(4-x^2 - y^2) , y/(4-x^2 - y^2), 1) or you can take ∇S / dS/dz = ( dS/dx, dS/dy, dS/dz) / dS/dz.. .you will get the same answer ∇S = ( 2x, 2y, 2z) ∇S / dS/dz = (x/z, y/z, 1) As for the actual integration, it looks like part of your k term has been cut off above..
Positive: 66.666666666667 %

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