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sets of integers. Help!?

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  • sets of integers. Help!?


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Answer #1 | 20/12 2013 05:16
√36 × √-1 = 6i √-36 × √1 = 6i - - - - - - - - - - - - - - - √-36 - √0 = 6i √-144 - √-36 = 6i - - - - - - - - - - - - - - -
Answer #2 | 20/12 2013 05:16
1] (-1,36),(-6,6) : (a,b) 2] (-100,-16),(-81,-9): (c,d)
Answer #3 | 20/12 2013 05:23
√a. √b = 6i or squaring both sides we get ab = -36; a = 6 and b = -6 or a = -9 and b = 4.; and so on √c - √d = 6i ---------- (1) or Let c = -49 and d = -1; This satisfies the given equation. LHS = 7i - i = 6i

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