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Sec alpha+tan alpha =2 then value of sin alpha where 0<@<90?

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  • Sec alpha+tan alpha =2 then value of sin alpha where 0<@<90?


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Answer #4 | 27/10 2014 18:04
1 / cos α + sin α / cos α = 2 1 + sin α = 2 cos α 1 + sin²α + 2 sin α = 4 cos²α 1 + sin²α + 2 sin α = 4 (1 - sin²α ) 1 + sin²α + 2 sin α = 4 - 4 sin²α 5 sin²α + 2 sin α - 3 = 0 ( 5 sin α - 3 ) ( sin α + 1 ) = 0 sin α = 3/5 _______for 1st quadrant α
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O is almost always -2. Just add up the charges 2 * Cl + (-2) = 0 because for the first one, there is no net charge. Cl = +1 Second, Cl + 2 * (-2) = -1 because this anion has a -1 charge. Cl = +3 Repeat for the last. You get +5
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Answer #8 | 27/10 2014 10:01
secα + tanα = 2 1/cosα + sinα/cosα = 2 (1+sinα)/cosα = 2 1 + sinα = 2 cosα sin²α + 2sinα + 1 = 4cos²α sin²α + 2sinα + 1 = 4−4sin²α 5sin²α + 2sinα − 3 = 0 (sinα + 1) (5sinα − 3) = 0 sinα = −1 or 3/5 Since 0 < α < 90, then sinα > 0 sinα = 3/5
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Answer #13 | 27/10 2014 11:04
1 / cos α + sin α / cos α = 2 1 + sin α = 2 cos α 1 + sin²α + 2 sin α = 4 cos²α 1 + sin²α + 2 sin α = 4 (1 - sin²α ) 1 + sin²α + 2 sin α = 4 - 4 sin²α 5 sin²α + 2 sin α - 3 = 0 ( 5 sin α - 3 ) ( sin α + 1 ) = 0 sin α = 3/5 _______for 1st quadrant α
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Answer #14 | 27/10 2014 17:01
secα + tanα = 2 1/cosα + sinα/cosα = 2 (1+sinα)/cosα = 2 1 + sinα = 2 cosα sin²α + 2sinα + 1 = 4cos²α sin²α + 2sinα + 1 = 4−4sin²α 5sin²α + 2sinα − 3 = 0 (sinα + 1) (5sinα − 3) = 0 sinα = −1 or 3/5 Since 0 < α < 90, then sinα > 0 sinα = 3/5
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