As you have two different variables, you need two sets of limits.

Answer #2 | 30/12 2013 06:07

no. It is not possible. since y also is a variable,you must also have another integration with respect to y.
Integrating mean finding the area of the a function with in the given limits.You are integrating 1/(x+y) with limits 'a' to 'b'(It means you are finding the area of graph from a to b for a graph with equation 1/(x+y) ), y also is a variable so it may be any value within the given limits. If you do integration directly it mean you are considering y as constant.
hope you got it.

Answer #3 | 30/12 2013 07:00

b
∫ dx / (x + y)
a
[ log (x + y) ]________limits a to b for variable x
log ( b + y ) - log (a + y)
log [ (b + y) / (a + y) ]

Answer #4 | 30/12 2013 08:07

If you do a simple ( and very simple ) indefinite integral you get ln(x+y)+K ... K = constant of integration.

Answer #1| 30/12 2013 03:06