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In the expansion of (6x-5)(3x=4), what is the coefficient of x?

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  • In the expansion of (6x-5)(3x=4), what is the coefficient of x?


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Answer #1 | 12/02 2014 01:57
−5*3 + 6*=4 If = is supposed to be +, then we get: −5*3 + 6*4 = 9 If = is supposed to be −, then we get: −5*3 + 6*−4 = −39
Answer #2 | 12/02 2014 02:01
6x-5)(3x-4) Coefficnt of x is -39 18x^2-24x-15x+20
Answer #3 | 12/02 2014 01:59
Did you meant (6x - 5)(3x - 4) ? (6x - 5)(3x - 4) = 6x(3x - 4) - 5(3x - 4) = 18x^2 - 24x - 15x + 20 = 18x^2 - 39x + 20 The coefficient of x is -39.
Answer #4 | 12/02 2014 01:55
a coefficient is the number beside the variable (in this case x), so for your problem you will have to expand the equation by multiplying it out (using FOIL or whatever process you have been taught) and then give the number that appears beside x, as your final answer will give a term that looks like Ax^2 + Bx + C (ABC represent numbers, and the +'s could be -'s). I would try to help by expanding it out and explaining, but there's something wrong with the question. The second term can't be 3x=4 (unless you're doing some higher math I've never seen, and I've already taken calculus...) Is it 3x+4 or 3x-4? EDIT: the people below are right (6x-5)(3x+4) = 18x^2-15x+24x-20 = 18x^2+9x-20 Thus 9 is the coefficient of x. (6x-5)(3x-4) = 18x^2-15x-24x+20 = 18x^2-39x+20 Thus -39 is the coefficient of x.
Answer #5 | 13/02 2014 04:21
"Given if your question is (6x-5)(3x+4) =>18x^2+24x-15x-20 =>18x^2+9x-20 then coefficient of x is 9 or if your question is (6x-5)(3x-4) =>18x^2-24x-15x+20 =>18x^2-39x+20 then the coefficient of x is -39"
Answer #6 | 12/02 2014 05:34
-39 see step by step solution: http://symbolab.com/solver/expand-calculator/Expand%20(6x-5)(3x-4) hope this helps
Answer #7 | 13/02 2014 22:37
According Formula = (a+b)(c+d)=ac+ad+bc+bd (6x - 5) (3x -4) = 6x3x² -6x4 - 5x3x + 5x4 = 18x² - 24 -15x + 20 = 18x² -39x +20 The coefficient of x is -39

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