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If a kick-boxer kicks his opponent with a force of 60N, what force will he experience?

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  • If a kick-boxer kicks his opponent with a force of 60N, what force will he experience?


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Answer #1 | 02/01 2014 13:10
60N. Newton's 3rd. law.
Answer #2 | 02/01 2014 13:16
Every action has an equal and opposite reaction, so they will also feel 60N of force in their foot.
Answer #3 | 02/01 2014 13:49
A force of 60 N would have little effect on the opponent. It doesn't work like this. Certainly IF he applied 60 N via his foot then his FOOT would also feel that 60 N. Every action has an equal and opposite reaction. Because of the momentum of the leg the rest of his body would not feel that force. In fact the situation is a bit different. He applies 60 N for perhaps 1/10 part of a second as he accelerates his leg. When the foot hits a solid object ( his opponent ) it stops suddenly. As momentum ( and impulse ) are conserved, F1 t1 = F2 t2 60 / 10 = F2 / 1000 ( taking 1/1000 sec as the time of the collision just as a demonstration. ) F2 = 6000N Both his foot and the opponent feel this 6000 N but the kick boxer's body only feels the original applied 60 N Hence it hurts his opponent more than it hurts him.

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