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# I have no clue with this one. Can someone help me please?

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• I have no clue with this one. Can someone help me please?

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Answer #1 | 30/12 2013 05:51
If you double the first equation, then the y terms will cancel each other out when you add the equations. 6x + 4y = 8 <-- first equation doubled 5x - 4y = 3 ---------------- <-- add the equations 11x      = 11 Divide both sides by 11 to isolate x x = 1 <-- answer for x Now you can find y by subbing "1" in for "x" 3x + 2y = 4 1) Replace x with 1 3*1 + 2y = 4 same as 3 + 2y = 4 Subtract 3 from both sides 2y = 1 Divide both sides by 2 y = 1/2 <-- answer for y Answer: (1, 0.5)
Answer #2 | 30/12 2013 05:53
It's simple. What you need to do is 1) Try to eliminate and of the variable (x or y). 2) We can do it by multiplying both equations by a number such that x of both or y or both become same. eg: if we multiply eq 1 with 2 6x + 4y = 8 And equation 2 will remain same as it is. 5x-4y=3; Now we can eliminate y by adding both of these equations. 6x + 4y + 5x - 4y = 8 + 3 11x = 11 x = 1 Put x in any of the equation and you get value of y 3x + 2y = 4 3 + 2y = 4 y = 1/2 Answer : (1,0.5)
Answer #3 | 30/12 2013 05:57
3x + 2y = 4 5x - 4y = 3 multiply first equation by 2, add to second equation: 6x + 4y = 8 5x - 4y = 3 ______________ 11x = 11 x = 11/11 = 1 using first equation: 3(1) + 2y = 4 2y = 1 y = 1/2 check using second equation: 5(1) - 4(1/2) = 3 5 - 2 = 3 checks solution set: (1, 1/2) (first choice) - .--

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