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How to solve this maths problem!?

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  • How to solve this maths problem!?


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Answer #1 | 30/12 2013 05:05
(1-1/x)^2=2 1 - 1/x = √2 or 1 - 1/x = -√2 -1/x = √2 - 1 or -1/x = -√2 - 1 1/x = 1 - √2 or 1/x = 1 + √2 x = 1/(1 - √2) or x = 1/(1 + √2) x = (1 + √2)/(1 + √2) 1/(1 - √2) or x = (1 - √2)/(1 - √2) 1/(1 + √2) x = (1 + √2)/(1 - 2) or x = (1 - √2)/(1 - 2) x = -1 - √2 or x = -1 + √2
Positive: 66.666666666667 %
Answer #2 | 30/12 2013 05:15
First make it like [(x-1)/x]^2=2 Open brackets and an equation will be formed like X^2+2x-1=0 Now solve this quadratic equation and you will get your desired answers You cannot take root on other side because expression on lhs may be positive or negative for eg: (x)^2 =4 X can be 2 or -2 You cannot solve it like x=root4=2 As -2 is also the possibility
Positive: 33.333333333333 %

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