(1-1/x)^2=2
1 - 1/x = √2 or 1 - 1/x = -√2
-1/x = √2 - 1 or -1/x = -√2 - 1
1/x = 1 - √2 or 1/x = 1 + √2
x = 1/(1 - √2) or x = 1/(1 + √2)
x = (1 + √2)/(1 + √2) 1/(1 - √2) or x = (1 - √2)/(1 - √2) 1/(1 + √2)
x = (1 + √2)/(1 - 2) or x = (1 - √2)/(1 - 2)
x = -1 - √2 or x = -1 + √2

Positive: 66.666666666667 %

Answer #2 | 30/12 2013 05:15

First make it like [(x-1)/x]^2=2
Open brackets and an equation will be formed like
X^2+2x-1=0
Now solve this quadratic equation and you will get your desired answers
You cannot take root on other side because expression on lhs may be positive or negative for eg:
(x)^2 =4
X can be 2 or -2
You cannot solve it like x=root4=2
As -2 is also the possibility

Answer #1| 30/12 2013 05:0566.666666666667 %