How to solve 4(6y+3)>28 and also how to solve 2x^2-2x-40<0?

Answers

Answer #1 | 22/05 2017 23:14

Question 1
6y + 3 > 7
6y > 4
y > 2/3
Question 2
x² - x - 20 < 0
[ x - 5 ] [ x + 4 ] < 0
_______________-4__________5________
x - 5_____-ve_________-ve____0___+ve____
x + 4____-ve_____0___+ve________+ve___
product__+ve____ 0___-ve____0___+ve____
solution set is {x : -4 < x < 5 }

Answer #2 | 22/05 2017 22:48

I'll give you some general theory first. If you have a continuous function (which polynomials are, and [thus] are connected as well) we note that the only way for a function to change sign is to pass through 0.
Thus, if we inspect the sign of the function between the x-coordinates where the function hits zero, we can (in terms of positivity and negativity) determine the behavior of the polynomial.
So, we can get the second one to be x^2 - x - 20 < 0, i.e. (x - 5)(x + 4) < 0. Thus, we hit zero at x = 5 and x = -4. Then, since the sign doesn't change between these points, we can just pick a point in each interval and see where negativity holds. Inspection tells me only when x is in (-4, 5) do we have negativity.
For the first, just solve, 6y + 3 > 7, 6y > 4, y > 2/3.

Answer #1| 22/05 2017 23:14