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How to integrate (1+2 (y^2))/y?

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  • How to integrate (1+2 (y^2))/y?


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Answer #1 | 14/01 2014 09:49
int (1/y + 2y) dy = ln|y| + y^2 + C
Positive: 100 %
Answer #2 | 14/01 2014 10:37
[1 + 2(y^2)]/y =[(1/y) + 2(y^2)/y] =[(1/y) + (2y)] integrate [(1/y) + (2y)]dy = ln |y| + 2(y^2)/2 + c = ln |y| + y^2 + c As simple as that!!!!!!!!!!!!
Positive: 100 %
Answer #3 | 14/01 2014 10:45
step by step solution: http://symbolab.com/solver/integral-calculator/%5Cint%20%5Cfrac%7B(1%2B2%20(y%5E%7B2%7D))%7D%7By%7Ddy hope this helps
Positive: 100 %
Answer #4 | 14/01 2014 11:44
∫ dy / y + ∫ 2y dy = log y + y² + C
Positive: 100 %
Answer #5 | 14/01 2014 23:59
int (1+ 2y^2)/y dy = int 1/y dy + int 2y dy = logy + y^2 + C
Positive: 100 %

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