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how to factorise this?

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• how to factorise this?

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Answer #1 | 30/12 2013 05:26
Let ( p+q) be = x x^2 + 5x = x ( x+5) = (p+q) ( p+q+5) ANSWER
Positive: 62.5 %
Answer #2 | 30/12 2013 04:10
(p+q)^2+5(p+q) (p+q)(p + q)+5(p+q) The term (p+q) is common between the two 'added' terms, so is 'taken out'. Hence (p+q)[(p+q) + 5] Removing the brackets (p+q)[p + q + 5]) Done!!!!
Positive: 60 %
Answer #3 | 30/12 2013 04:45
Just put in evidence the term (p+q)... it is so (p+q)( p + q + 5) ... OK! the answer is correct.
Positive: 55.555555555556 %
Answer #4 | 30/12 2013 03:59
Well, (p+q) is a common factor, so you can take it out.
Positive: 55.555555555556 %
Answer #5 | 30/12 2013 04:11
x² + 5x x (x + 5) (p + q) ( p + q + 5 )
Positive: 44.444444444444 %
Answer #6 | 30/12 2013 04:16
(p+q)^2 + 5(p+q) = (p+q)(p+q) + 5(p+q) (p+q) is a common factor of the two terms. Take this common factor out to get: = (p+q)[(p+q)+ 5] or = (p+q)(p+q+5)
Positive: 33.333333333333 %

Possible answer

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