(p+q)^2+5(p+q)
(p+q)(p + q)+5(p+q)
The term (p+q) is common between the two 'added' terms, so is 'taken out'.
Hence
(p+q)[(p+q) + 5]
Removing the brackets
(p+q)[p + q + 5])
Done!!!!

Positive: 62.5 %

Answer #2 | 30/12 2013 05:26

Let ( p+q) be = x
x^2 + 5x = x ( x+5) = (p+q) ( p+q+5) ANSWER

Positive: 57.142857142857 %

Answer #3 | 30/12 2013 03:59

Well, (p+q) is a common factor, so you can take it out.

Positive: 57.142857142857 %

Answer #4 | 30/12 2013 04:45

Just put in evidence the term (p+q)...
it is so (p+q)( p + q + 5) ... OK! the answer is correct.

Positive: 57.142857142857 %

Answer #5 | 30/12 2013 04:11

x² + 5x
x (x + 5)
(p + q) ( p + q + 5 )

Positive: 42.857142857143 %

Answer #6 | 30/12 2013 04:16

(p+q)^2 + 5(p+q)
= (p+q)(p+q) + 5(p+q)
(p+q) is a common factor of the two terms. Take this common factor out to get:
= (p+q)[(p+q)+ 5]
or
= (p+q)(p+q+5)

Answer #1| 30/12 2013 04:1062.5 %