Given the center of the circle?

Short Answer: False Long Answer: Ok, so first you find the distance from the center of the circle to a point on the circle (2,6), to find the radius. (1,3) to (2,6) Use pythogarem theorem: you are going up one and to the right 3 So you have sides, 1 and 3 so (1^2 + 3^2) = mystery side ^ 2 mystery side ^ 2 = 10 mystery side (let's call it x) x = sq rt of 10 so, if (-3,6) is on the circle, it has to be exactly sq rt of 10 units away from (1,3), because all points on circle are equidistant from the center. So, from 1,3 to -3,6 you go left 4 and up 3, So you have sides 4 and 3, and in the pythogaream theorem, if one side is 3, another side is 4, then the last side must be 5 (3^2+4^2 = 5^2). Keep in mind this is only for RIGHT triangles. So, from 1,3 to 2,6 is sqrt of 10, but to -3,6 it is 5 since sqrt of 10 is not equal to 5 the points are not equidistant from the center so -3,6 is not on the circle so the answer is FALSE

The distance from the center to (2, 6) is √[(6 - 3)² + (2 - 1)²] = √(10) The distance from the center to (-3, 6) is √[(6 - 3)² + (-3 - 1)²] = √(25) = 5, so the point is not on the given circle. False.

False