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Find the vertex, and any two convenient points to sketch the graph of the following function. y=x^2−6?

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  • Find the vertex, and any two convenient points to sketch the graph of the following function. y=x^2−6?


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Answer #1 | 27/12 2013 15:19
When x equals zero, y equals -6. Plot a point at (0, -6). When x equals both 1 and -1, y equals 1 - 6 or -5. Plot points at (-1, -5) and (1, -5). If those points aren't enough to draw a smooth curve through them, add a few more points: When x equals both -2 and 2, y equals 4 - 6 or -2. Plot points at (-2, -2) and (2, -2). Plot more points as need for more integer values of x. (The graph is symmetrical across the y-axis.)
Answer #2 | 27/12 2013 15:21
vertex form is y = a(x - h)² + k where (h, k) is the vertex. so for given equation vertex is (0, -6) then two more points could be (1, -5) and (2, -2)

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