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Find the value of X if √2/(X+√2) = 1/(X-√2)?

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  • Find the value of X if √2/(X+√2) = 1/(X-√2)?


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Answer #1 | 23/12 2013 03:52
2/(X+2) = 1/(X-2) cross multiply and we get, 2(x-2)=1(x+2) 2x-4 = x+2 x=6
Answer #2 | 23/12 2013 04:13
√2/(X+√2) = 1/(X-√2) cross-multiply: SQR(2)[x - SQR(2)] = x + SQR(2) distribute: xSQR(2) - 2 = x + SQR(2) xSQR(2) - x = 2 + SQR(2) x(SQR(2) - 1) = 2 + SQR(2) x = [SQR(2) + 2]/[SQR(2) - 1] - .--
Answer #3 | 23/12 2013 04:33
cross multiply √2x-2=x+√2 x(√2-1)=√2+2 x(√2-1)=√2(√2+1) x=√2(√2+1)/(√2-1) multiply with conjugate on both deno and nume we get x=√2/(√2-1)^2

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