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find f(t) for L{f(t)}=[1/2s^2]-[(2e^-4s)/(s(1-e^-4s))]?
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find f(t) for L{f(t)}=[1/2s^2]-[(2e^-4s)/(s(1-e^-4s))]?
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Answer #1
| 23/12 2013 17:17
Hi L{f(t)} = (1/2) (1/s^2) - [ (2e^-4s) /(s(1-e^-4s))] L{f(t)} = (1/2) (1/s^2) - (2/s) [ (e^-4s) /(1-e^-4s)] L{f(t)} = (1/2) (1/s^2) - (2/s) [ e^-4s + e^-8s + e^-12s +...] f(t) = (1/2) t u(t) - 2 (u( t - 4) + u( t - 8) + u( t - 12) + .... )
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Answer #1| 23/12 2013 17:17