# F(n)= 7+n+f(n-1), where f(0)=1 Can anyone help with this one? :)?

• F(n)= 7+n+f(n-1), where f(0)=1 Can anyone help with this one? :)?

Answer #1 | 10/05 2016 10:31
Using your rule f(1) = 7 + 1 + 1 = 9 f(2) = 7 + 2 + 9 = 18 f(3) = 7 + 3 + 18 = 28 . . .
Positive: 50 %
Anonymous716282 | 08/06 2021 23:43
cialis 2.5 mg daily
Positive: 0 %
Anonymous102526 | 08/06 2021 22:54
new payday lenders payday loans store
Positive: 0 %
Anonymous543676 | 08/06 2021 23:52
payday loans nj
Positive: 0 %
Anonymous26801 | 09/06 2021 00:39
best online loans instant approval
Positive: 0 %
Anonymous215024 | 10/06 2021 07:45
www payday loans rise loans
Positive: 0 %
Anonymous954364 | 09/06 2021 20:26
cheap installment loans
Positive: 0 %
Anonymous675282 | 09/06 2021 02:13
same day loans no credit check
Positive: 0 %
Anonymous437452 | 08/06 2021 22:00
quick loans no credit check
Positive: 0 %
Anonymous958634 | 08/06 2021 11:37
payday loans with no credit checks consolidation
Positive: 0 %
Answer #11 | 10/05 2016 10:35
Well, @unknonwn : thank you : corrected let n = 2p+1 (or : p = (n - 1)/2 ) then 1^2+3^2+5^2+7^2+.....+n^2 = Σ(k from 0 to p) (2k + 1)^2 = Σ(k from 0 to p) [ 4k^2 + 4k + 1 ] = 4 Σ(k from 0 to p) k^2 + 4 Σ(k from 0 to p) k + Σ(k from 0 to p) 1 = 4 p(p+1)(2p+1)/6 + 4 p(p+1)/2 + p + 1 hope it' ll help !!
Positive: 0 %
Answer #12 | 10/05 2016 10:42
1² + 3² + 5² + 7² + ... + n² = 1² + 2² + 3² + .... + n² - 2² - 4² - 6² - ... - (n-1)² = n(n+1)(2n+1)/6 - 2²(1² + 2² + ... + ((n-1)/2)²) = n(n+1)(2n+1)/6 - 4 ((n-1)/2)((n-1)/2+1)(n)/6 = (n/6) ((n+1)(2n+1) - (n-1)(n+1)) = n(n+1)(n+2)/6 ( = ((n+2)!/(n-1)!)/3! = C(n+2,3) ) Michael : Sum(k from 0 to p) 1 = p + 1 and not p
Positive: 0 %
Answer #13 | 10/05 2016 03:42
1² + 3² + 5² + 7² + ... + n² = 1² + 2² + 3² + .... + n² - 2² - 4² - 6² - ... - (n-1)² = n(n+1)(2n+1)/6 - 2²(1² + 2² + ... + ((n-1)/2)²) = n(n+1)(2n+1)/6 - 4 ((n-1)/2)((n-1)/2+1)(n)/6 = (n/6) ((n+1)(2n+1) - (n-1)(n+1)) = n(n+1)(n+2)/6 ( = ((n+2)!/(n-1)!)/3! = C(n+2,3) ) Michael : Sum(k from 0 to p) 1 = p + 1 and not p
Positive: 0 %
Answer #14 | 10/05 2016 03:35
Well, @unknonwn : thank you : corrected let n = 2p+1 (or : p = (n - 1)/2 ) then 1^2+3^2+5^2+7^2+.....+n^2 = Σ(k from 0 to p) (2k + 1)^2 = Σ(k from 0 to p) [ 4k^2 + 4k + 1 ] = 4 Σ(k from 0 to p) k^2 + 4 Σ(k from 0 to p) k + Σ(k from 0 to p) 1 = 4 p(p+1)(2p+1)/6 + 4 p(p+1)/2 + p + 1 hope it' ll help !!
Positive: 0 %
Anonymous992618 | 07/06 2021 05:15
monthly installment
Positive: 0 %
Anonymous424893 | 07/06 2021 04:06
unsecured loans personal loan bad credit
Positive: 0 %
Anonymous857809 | 07/06 2021 00:30
loan no credit check
Positive: 0 %
Anonymous266583 | 10/06 2021 14:41
kamagra 100mg for sale best price
Positive: 0 %
Anonymous211029 | 11/06 2021 00:31
payday loans in las vegas nevada
Positive: 0 %
Anonymous853720 | 13/06 2021 00:38
metformin coupon pharmacy 5 viagra motilium generic generic tadalafil india sildenafil 110 mg capsule
Anonymous438578 | 13/06 2021 00:14
how to take out a loan
Anonymous167838 | 13/06 2021 00:53
Anonymous34901 | 13/06 2021 06:42
loans in arizona installment loans with bad credit
Anonymous719605 | 13/06 2021 08:55
order modafinil online india
Anonymous905623 | 13/06 2021 08:13
cash advances online loans without cosigner
Anonymous348065 | 13/06 2021 08:13
[url=https://yourpaydayloansonline.com/]loan application online[/url]
Anonymous234133 | 12/06 2021 17:16
sildenafil 80 mg
Anonymous171608 | 12/06 2021 15:05
payday loans online
Anonymous411053 | 11/06 2021 13:58
lasix daily
Anonymous891014 | 11/06 2021 12:22
guarantee loan
Anonymous722224 | 11/06 2021 14:34
best personal loans
Anonymous943630 | 11/06 2021 22:58
same day loans for bad credit
Anonymous380761 | 12/06 2021 04:44
installment loans direct lenders florida payday loans
Anonymous90276 | 12/06 2021 01:48
discover personal loans
Anonymous467681 | 11/06 2021 23:24
loan fast