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Algebra 1 Help Please!!!?

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  • Algebra 1 Help Please!!!?


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Answer #1 | 28/12 2013 20:24
The original number is 42. 4+2=6 6*7=42 24-18=6
Answer #2 | 28/12 2013 20:38
Ever since you are multiplying by 7, to solve any equation you will have to divide the original number by 7 eventually, That means that the original number is a multiple of 7, or you wouldn't be able to divide it. So the easiest thing to do is to list the 2-digit multiples of 7 and see which one fits the conditions. 14 21 28 35 etc 1) Try 14 first 1 + 4 = 5 5 * 7 = 35, not 14 2) Try 21 2 + 1 = 3 3 * 7 = 21 Bingo #1 Is this the right one? Answer: If you add the digits of 21 and multiply the sum by 7, you will get the original number. CHECK: If you reverse the digits (which will be 12) Then this new number 12 is 18 more than 3. WRONG. ~~~~~~~~~ Keep on trying. 28 would be 10*7 35 would be 8*7 42 would be 6*7 BINGO #2 Is it the right one? Answer: If you add the digits of 42 and multiply the sum by 7, you will get 42. CHECK: Reverse the digits. That gives you the new number 24. 24 should be 18 more than the sum of 2+4 24 = 18 + 6 24 = 24 CHECK ~~~~~~~~~~~~~~~ The original number is 42 <-- answer 4 + 2 = 6 6 * 7 = 42 42 reversed is 24. 24 is 18 more than 4 + 2.

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