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A square is inscribed in a circle of radius 8cm. What is the area of square?

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  • A square is inscribed in a circle of radius 8cm. What is the area of square?


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Answer #1 | 13/02 2014 04:41
Diagonal of square = diameter = 16 cm Area of square = 16 X 16 =256, 256 /2 = 128 sq cm ANSWER
Answer #2 | 13/02 2014 04:45
the diagonal of the square will be equal to the diameter of the circle. the d = s√2 [where d is diagonal of the square and s is the side of the square using the 45-45-90 reference triangle] => s = d/√2 given the area of a square is A = s² => s² = d²/2 => s² = (2*8)²/2 => s² = 128 cm²
Answer #3 | 13/02 2014 04:44
The diameter is the diagonal of the square d = 16 Area of the square is (1/2)(diagonal)^2 Area = (16^2)/2 = 128cm^2 because you can see the square as a rhombus with equal diagonals
Answer #4 | 13/02 2014 04:50
d = 16 cm x² + x² = 16² 2x² = 256 x² = 128 x = 8 √2 cm Area = x² = 128 cm²
Answer #5 | 13/02 2014 04:57
diagonal of the square=diametere of the circle=16cm. Arm or side of the square=diagonal / sq. root of 2= 11.3137 . Area= (side)^2= 128 cm^2
Answer #6 | 14/02 2014 06:17
128 sq cm.
Answer #7 | 14/02 2014 01:47
diagonal of square = 2*8 = 16cm side of square = x cm so x^2 + x^2 = 16^2 or 2x^2 = 16^2 area =x^2 = 16^2/2 = 256/2 = 128 cm^2

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