A square is inscribed in a circle of radius 8cm. What is the area of square?

Answers

Answer #1 | 13/02 2014 04:44

The diameter is the diagonal of the square
d = 16
Area of the square is (1/2)(diagonal)^2
Area = (16^2)/2 = 128cm^2
because you can see the square as a rhombus with equal diagonals

Positive: 100 %

Answer #2 | 13/02 2014 04:45

the diagonal of the square will be equal to the diameter of the circle.
the d = s√2 [where d is diagonal of the square and s is the side of the square using the 45-45-90 reference triangle]
=> s = d/√2
given the area of a square is A = s²
=> s² = d²/2
=> s² = (2*8)²/2
=> s² = 128 cm²

Answer #3 | 13/02 2014 04:41

Diagonal of square = diameter = 16 cm
Area of square = 16 X 16 =256,
256 /2 = 128 sq cm ANSWER

Answer #4 | 13/02 2014 04:50

d = 16 cm
x² + x² = 16²
2x² = 256
x² = 128
x = 8 √2 cm
Area = x² = 128 cm²

Positive: 0 %

Answer #5 | 13/02 2014 04:57

diagonal of the square=diametere of the circle=16cm. Arm or side of the square=diagonal / sq. root of 2= 11.3137 . Area= (side)^2= 128 cm^2

Answer #6 | 14/02 2014 06:17

128 sq cm.

Positive: 0 %

Answer #7 | 14/02 2014 01:47

diagonal of square = 2*8 = 16cm
side of square = x cm
so x^2 + x^2 = 16^2
or 2x^2 = 16^2
area =x^2 = 16^2/2 = 256/2 = 128 cm^2

Answer #1| 13/02 2014 04:44100 %