A push of 180 N and pull of 350 N act simultaneously at a point. Find the resultant of the forces, if the angle between them be 135 degree?

Answers

Answer #1 | 01/02 2015 10:34

Let the resultant be R.
R^2 = P^2 + Q^2 + 2PQ cos (theta)
= (350)^2 + (180)^2 + 2 (350) (180) cos (135°)
= 65804.55
R = 256.52 newton
Let R make an angle x with P.
tan (x) = Q sin (theta) / (P + Q cos (theta))
= 180 sin (135°) / (350 + 180 cos (135°))
= 0.57
x = arctan (0.57) = 29.68°

Positive: 39.393939393939 %

Answer #2 | 01/02 2015 18:34

Let the resultant be R.
R^2 = P^2 + Q^2 + 2PQ cos (theta)
= (350)^2 + (180)^2 + 2 (350) (180) cos (135°)
= 65804.55
R = 256.52 newton
Let R make an angle x with P.
tan (x) = Q sin (theta) / (P + Q cos (theta))
= 180 sin (135°) / (350 + 180 cos (135°))
= 0.57
x = arctan (0.57) = 29.68°

Answer #1| 01/02 2015 10:3439.393939393939 %