# 1.60g of a metal were dissolved in HNO3 to prepare its nitrate. The nitrate was strongly heated to give 2g oxide. Calculate equivalent weight of metal.?

• 1.60g of a metal were dissolved in HNO3 to prepare its nitrate. The nitrate was strongly heated to give 2g oxide. Calculate equivalent weight of metal.?  Answer #1 | 14/05 2015 08:40 -453x + 453y = 3624
Positive: 66.666666666667 %
Answer #2 | 14/05 2015 08:47 y=mx+b, m=(6-3)/(-2--5)=3/3=1 y=x+b using (-5,3) we get 3=-5+b, so b=8 y=x+8 y-x=8
Positive: 66.666666666667 %
Answer #3 | 14/05 2015 08:22 Gradient => (6 - 3)/(-2 - (-5)) = 3/3 = 1 so, equation is y - 3 = x + 5 i.e. y - x = 8 :)>
Positive: 50 %
Answer #4 | 14/05 2015 15:47 y=mx+b, m=(6-3)/(-2--5)=3/3=1 y=x+b using (-5,3) we get 3=-5+b, so b=8 y=x+8 y-x=8
Positive: 50 %
Answer #5 | 14/05 2015 08:26 y=m(x-a) +b this is the form of the function of a line. m is the slope of a line, (a,b) is a point that the line passes through. we need a slope first. m=(y1-y2)/(x1-x2) =(3-6)/((-5)-(-2)) =-3/-3 =1 so the slope is 1 pick one of the points to replace with (a,b). Since the line passes through the points, both points will satisfy the equation. y=1.(x-(-5))+3 y=x+8 in the form ax+by=c is >>> -x+y=8
Positive: 50 %
Answer #6 | 14/05 2015 15:26 y=m(x-a) +b this is the form of the function of a line. m is the slope of a line, (a,b) is a point that the line passes through. we need a slope first. m=(y1-y2)/(x1-x2) =(3-6)/((-5)-(-2)) =-3/-3 =1 so the slope is 1 pick one of the points to replace with (a,b). Since the line passes through the points, both points will satisfy the equation. y=1.(x-(-5))+3 y=x+8 in the form ax+by=c is >>> -x+y=8
Positive: 50 %
Answer #7 | 14/05 2015 15:40 -453x + 453y = 3624
Positive: 33.333333333333 %
Answer #8 | 14/05 2015 15:22 Gradient => (6 - 3)/(-2 - (-5)) = 3/3 = 1 so, equation is y - 3 = x + 5 i.e. y - x = 8 :)>
Positive: 0 %
Anonymous196608 | 26/09 2020 20:34 1.6/ E=2/E+8 E=32 