# Find the value of X if √2/(X+√2) = 1/(X-√2)?

• Find the value of X if √2/(X+√2) = 1/(X-√2)?

Answer #1 | 23/12 2013 03:52
2/(X+2) = 1/(X-2) cross multiply and we get, 2(x-2)=1(x+2) 2x-4 = x+2 x=6
Positive: 95 %
Answer #2 | 23/12 2013 04:13
√2/(X+√2) = 1/(X-√2) cross-multiply: SQR(2)[x - SQR(2)] = x + SQR(2) distribute: xSQR(2) - 2 = x + SQR(2) xSQR(2) - x = 2 + SQR(2) x(SQR(2) - 1) = 2 + SQR(2) x = [SQR(2) + 2]/[SQR(2) - 1] - .--
Positive: 89 %
Answer #3 | 23/12 2013 04:33
cross multiply √2x-2=x+√2 x(√2-1)=√2+2 x(√2-1)=√2(√2 +1) x=√2(√2+1)/(√2-1) multiply with conjugate on both deno and nume we get x=√2/(√2-1)^2
Positive: 69 %

... means the absolute-value of the error e x − (1 + x + x 2 /2) ... or the union–find algorithm. ... the big O notation (number 2 in the lists above) ...
Positive: 95 %
In function notation, the "x" in "f(x) ... (x) = x 2 + 2x – 1, find f(–3). f ... Which half of the function you use depends on what the value of x is.
Positive: 90 %
To multiply fractions, multiply straight across the top then straight across the bottom Order of operations calls for multiplication before subtraction