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A solution was prepared by dissolving 12.3 grams of NaCl in 98 grams of water. How can I find the molal concentration of this solution?

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  • A solution was prepared by dissolving 12.3 grams of NaCl in 98 grams of water. How can I find the molal concentration of this solution?


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Answer #1 | 29/04 2014 17:16
mw of NaCl = 58.44 # of moles of NaCl = 12.3/58.44 = 0.21 moles molality = moles of solute / kg. of solvent = 0.21 moles / .098 Kg = 2.14
Positive: 57 %
Answer #2 | 29/04 2014 18:58
c= * m solute = 12.3g m solution = 98g c= msolute/msolution x 100 c= 12.3/98 x 100 c= 12.55102....
Positive: 51 %

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